If one face of a prism of angle 30∘ and refractive index μ=√2 is silvered, the incident ray retraces its initial path. The angle of incidence is
A
45∘
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B
30∘
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C
60∘
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D
15∘
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Solution
The correct option is A45∘
If the incident ray retraces its path, then angle of incidence at the silvered surface =90∘ From the property of ΔAED, we can find ∠ADE=60∘ Then, angle of refraction r=90∘−60∘=30∘ Now, using Snell’s law, 1×sini=μ×sin30∘ ⇒sini=1√2 ∴i=45∘