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Question

If one factor of the equation x3+7kx2−4kx+12 is (x+3), then the value of k is

A
5
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B
15
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C
1317
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D
1713
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Solution

The correct option is B 15
f(x)=x3+7Kx24Kx+12
(x+3) is a factor of f(x)
So, f(3)=0
27+63K+12K+12=0
75K=15
=K=15

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