If one gram of a metal carbonate gave 0.56g of its oxide on heating then equivalent weight of metal will be
Open in App
Solution
let metal carbonate be : MCO3 and metal oxide is MO MCO3 ----> MO + CO2 1gm 0.56g so the oxide is CaO (M.wt = 56) and metal carbonate is CaCO3 (M. wt = 100) metal is Ca (M.wt = 40) and metal ion is Ca++ its eq. wt ( 40 /2 ) = 20