If one mole of a gas (mol.wt-40) occupies a volume of 20litres, under the same conditions of temperature and pressure the volume occupied by 2 moles of gas B (mol.wt=80) is
The correct option is D. 40 L
PV = nRT
P1V1P2V2 = n1T1n2T2
20V2 = 12
V2=40lts