If one mole of a gas (mol.wt-40) occupies a volume of 20 litres, under the same conditions of temperature and pressure the volume occupied by 2 moles of gas (mol.wt=80) is

80 L

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60 L

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50 L

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40 L

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Solution

The correct option is D
40 L

PV = nRT

$\frac{P_{1} V_{1}}{P_{2} V_{2}}$ = $\frac{n_{1} T_{1}}{n_{2} T_{2}}$

$\frac{20}{V_{2}}$ = $\frac{1}{2}$

$V_{2}$ = 40 lts

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If one mole of a gas (mol.wt-40) occupies a volume of 20 litres, under the same conditions of temperature and pressure the volume occupied by 2 moles of gas (mol.wt=80) is

The correct option is D 40 L PV = nRT P1V1P2V2 = n1T1n2T2 20V2 = 12 V2 = 40 lts

The correct option is D
40 L

PV = nRT

$\frac{P_{1} V_{1}}{P_{2} V_{2}}$ = $\frac{n_{1} T_{1}}{n_{2} T_{2}}$

$\frac{20}{V_{2}}$ = $\frac{1}{2}$

$V_{2}$ = 40 lts