If one mole of the original complex is treated with excess of $P b (N O_{3})_{2}$ solution, then the number of moles of white precipitate (of $P b C l_{2})$ formed will be :

0.5

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Solution

The correct option is A 0.5
The complex $[C o B r C l (e n)_{2}] C l . H_{2} O$ contains one chlorine atom in the ionization sphere.
One molecule of lead dichloride contains two chlorine atoms.
Thus, one mole of complex will react with half mole of lead nitrate to form half mole of lead chloride precipitate.

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If one mole of the original complex is treated with excess of Pb(NO3)2 solution, then the number of moles of white precipitate (of PbCl2) formed will be :

The correct option is A 0.5The complex [CoBrCl(en)2]Cl.H2O contains one chlorine atom in the ionization sphere.One molecule of lead dichloride contains two chlorine atoms.Thus, one mole of complex will react with half mole of lead nitrate to form half mole of lead chloride precipitate.

If one mole of the original complex is treated with excess of $P b (N O_{3})_{2}$ solution, then the number of moles of white precipitate (of $P b C l_{2})$ formed will be :