The correct option is B 90∘,90∘,90∘
Let AB and CD be two lines Intersecting at O, such that, ∠AOD=90∘
Now, ∠AOD=∠COB=90∘ (Vertically opposite angles)
⟹∠AOD+∠DOB=180o (Angles on a straight line)
⟹90+∠DOB=180o
∠DOB=90∘
∠DOB=∠AOC=90∘ (Vertically opposite angles)
Thus, all angles are 90∘.