wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If one of the angles of a parallelogram is 24° less than twice the smallest angle. Find the smaller angles of a parallelogram

Open in App
Solution

First of all as parallelogram is a quadrilateral with opposite sides parallel so we can say the opposite angles are also parallel that is a parallelogram consist of two pair with same angle.

Now let x be the smallest angle of the parallelogram, Also as explained above there must be another angle equal to x as it is a parallelogram.

we remaining with two angles.

Now also it is given that the other angle is 24° less than twice of the smallest.

So we get angle to be

2x-24°

And same as x there must be another angle equal to 2x-24°

And as sum of all the angles of quadrilateral is 360°.

So adding all and euating with 360°.

2x-24+2x-24+x+x=360

6x=360+48

6x=408

x=68°

So the largest angle from here can be deduced

2*68–24

Which comes to be 112°.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Diagonals of a Parallelogram divides it into two congruent triangles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon