Question

If one of the diameter of the circle $x^2+y^2-2x-6y+6=0$ is a chord to the circle with centre $(2,1)$, then the radius of the circle is

• A. $\sqrt{3}$
• B. $\sqrt{2}$
• C. $3$
• D. $2$

Answer 1

The correct option is A $\sqrt{3}$

Center is $(1,3)$ and radius = $2$

If r = radius of second circle then,

$r^2=2^2+(3-1{)}^2+(2-1{)}^2$

$r\Rightarrow \sqrt{3}$