Question

If one of the diameters of the circle, given by the equation, $x^2+y^2-4x+6y-12=0$, is a chord of a circle S, whose centre is at (–3, 2), then the radius of S is:

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

$Eq.x^2+y^2-4x+6y-12=0$

$C_1;(2,-3),r_1=\sqrt{4+9+12}=5$

$C_2=(-3,2)$

$C_1{C}_2=\sqrt{5^2+5^2}=\sqrt{50}$

$Then,C_{2}A=\sqrt{5^2+(\sqrt{50}{)}^2}=\sqrt{75}=5\sqrt{3}$