If one of the pairs is given, then what is the probability that all the other required pairs can be determined?

4/10

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5/10

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5/11

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6/11

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Solution

The correct option is B
5/10

The correct option is (b).

If the pairs (BLUE, GREEN), (BLUE, PINK), (BLUE, PURPLE), (RED, PURPLE) and (YELLOW, PURPLE) are given, then all other pairs can be determined, while if the pairs (BLUE, YELLOW), (RED, YELLOW), (RED, PINK), (GREEN, PINK) and (GREEN, PURPLE) are given, then all other pairs cannot be determined. Therefore, required probability.

$= \frac{T o t a l n u m b e r o f f a v o u r a b l e c a s e s}{t o t a l n u m b e r o f p o s s i b l e c a s e s} = \frac{5}{10}$

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