Question

If one of the zeroes of the cubic polynomial $x^3+a{x}^2+bx+c$ is $1$, then

• A. $a+b+c=0$
• B. $a+b+c=-1$
• C. $a+b=c$
• D. $a+c=b$

Answer 1

The correct option is B $a+b+c=-1$

For the equation, $x^3+a{x}^2+bx+c$, one of the roots is 1
Put $x=1$ and equate it to $0.$
Then$1+a+b+c=0$
$⟹a+b+c=-1$