Question

If one of zeros of a polynomial 3x^2-8x+(2k+1) is 7 times of the Other find the value of k

Answer 1

3x²-8x+2k+1 a=3, b=-8 ,c=2k+1
suppose the zeroes of the equation are α and β . by the given condition α=7β
as we know , α+β=-b/a
7β+β=-(-8)/3
8β=8/3
β=8/3×1/8=1/3
αβ=c/a
7β×β=2k+1/3
7×1/3×1/3=2k+1/3
7/9=2k+1/3
21/9=2k+1
21/9-1=2k
12/9=2k
4/3=2k
4/6=k
k = 2/3