Question

If one root of $6x^2+13x+b+1=0$ is the reciprocal of the other root, then the value of $b$ is

Answer 1

$6x^2+13x+b+1=0$
Let the roots be $\alpha$ and $\frac{1}{\alpha }$
So, product of roots is,
$\alpha \times \frac{1}{\alpha }=\frac{b+1}{6}$
$\Rightarrow b+1=6$
$\Rightarrow b=5$