If one root of $5 x^{2} + 13 x + k = 0$ is reciprocal of the other, then

k = 0

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k = 5

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k = \frac{1}{6}

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k = 6

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Solution

The correct option is B $k = 5$
Let roots be $α, \frac{1}{α}$ , then
$α \times \frac{1}{α} = \frac{k}{5}$
$\Rightarrow k = 5$
Hence, option 'B' is correct.

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If one root of $5 x^{2} + 13 x + k = 0$ is reciprocal of the other, then k=

5 x^{2} + 13 x + k = 0

k =

5 x^{2} + 13 x + k = 0

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5 x^{2} + 13 x + k = 0

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