If one root of the equation 2 $x^{2}$ + ax + 6 = 0 is 3, then find the value of a

-8

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Solution

Step 1:- If one root of the equation 2 $x^{2}$ + ax + 6 = 0 is 3, then substitute x=3 in the equation,

Step 2:- 2 $(3)^{2}$ + 3a +6 =0,

$\Rightarrow$ 18 + 3a + 6=0 ,

Step 3:- 24 + 3a =0 ,

$\Rightarrow$ a=-8.

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