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Monotonically Increasing Functions

If one root o...

Question

If one root of the equation $i x^{2} - 2 (i + 1) x + (2 - i) = 0$ is $2 - i$ then the other root is

- i

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2 + i

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i

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2 - i

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Solution

The correct option is C $- i$
One root of the equation $i x^{2} - 2 (i + 1) x + (2 - i) = 0$ is $2 - i$
Let the other root is $α$
$α (2 - i) = \frac{2 - i}{i}$
$\Rightarrow α = \frac{1}{i} = - i$ ..... $[∵ i^{2} = - 1]$
Therefore, $- i$ is the other root.
Hence, option A is correct.

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