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Question

If one root of the equation (k2+1)x2+13x+4k=0 is reciprocal of the other, then k has the value

A
2+3
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B
23
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C
1
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D
none of these
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Solution

The correct option is B 23
(k2+1)x2+13x+4k=0
Let a and 1a be the roots
Products of the roots =1=4kk2+1
k24k+1=0
k=2±3
Ans: B

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