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Monotonically Increasing Functions

If one root o...

Question

If one root of the equation $x^{2} + (1 - 3 i) x - 2 (1 + i) = 0$ is $- 1 + i$ , then the other root is

- 1 - i

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\frac{(- 1 - i)}{2}

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i

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2 i

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Solution

The correct option is A $2 i$
Let another root of the equation
$x^{2} + (1 - 3 i) x - 2 (1 + i) = 0 i s α$
$∴ a + (- 1 + i) = - (1 - 3 i)$
$\Rightarrow a = - 1 + 3 i + 1 - i$
$= 2 i$
x2+(1−3i)x−2(1+i)=0isα

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