If one root of the equation x2−12x+3k=0 is square of the other, then k is
A
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A 9 Thegivenequationisx2−12x+3k=03kispositivehere.Soboththerootsarepositiveorboththerootsarenegative.Letonerootbeα∴otherrootisα2.Buta2ispositiveasitisasquaredterm.∴aisalsopositive.Soaspertherelationbetweenrootsandcoefficientsα+α2=12−−−−(1)andα×α2=3kwhichispositive.−−−−(2)From(1)α2+α−12=0⇒(α+4)(α−3)=0⇒α=−4,3Aspertheabovediscussionwetakethepositivevalueonly.Thereforeα=3.Substitutingforαinequation(2)3k=3×32⇒k=9(Ans)