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Question

If one root of the equation x2−12x+3k=0 is square of the other, then k is

A
3
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B
9
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C
6
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D
12
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Solution

The correct option is A 9
Thegivenequationisx212x+3k=03kispositivehere.Soboththerootsarepositiveorboththerootsarenegative.Letonerootbeαotherrootisα2.Buta2ispositiveasitisasquaredterm.aisalsopositive.Soaspertherelationbetweenrootsandcoefficientsα+α2=12(1)andα×α2=3kwhichispositive.(2)From(1)α2+α12=0(α+4)(α3)=0α=4,3Aspertheabovediscussionwetakethepositivevalueonly.Thereforeα=3.Substitutingforαinequation(2)3k=3×32k=9(Ans)

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