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Question

If one root of the equation x2+px+12=0 is 4, while the equation x2+px+12=0 has equal roots, then the value of q is:

A
494
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B
12
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C
3
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D
4
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Solution

The correct option is A 494
Since 4 is one of the roots of equation x2+px+12=0 so it must satisfy the equation.
16+4p+12=04p=28p=7
The other equation is x27x+q=0 whose roots are equal.
Let the root be α
Therefore sum of roots α+α=712α=7α=72
and product of roots α.α=qα2=qq=494.

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