If one root of the quadratic $2 x^{2} + p x - 4 = 0$ is $2$ , then the value of $p$ will be:

- 3

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Solution

The correct option is B $- 2$
$2 x^{2} + p x - 4 = 0$ has one root $2$

So it will satisfy the equation

$∴ 2 (2)^{2} + p (2) - 4 = 0$

$\Rightarrow p = - 2$

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If one root of the quadratic 2x2+px−4=0 is 2, then the value of p will be:

The correct option is B −22x2+px−4=0 has one root 2So it will satisfy the equation∴2(2)2+p(2)−4=0⇒p=−2

If one root of the quadratic $2 x^{2} + p x - 4 = 0$ is $2$ , then the value of $p$ will be:

The correct option is B $- 2$
$2 x^{2} + p x - 4 = 0$ has one root $2$

So it will satisfy the equation

$∴ 2 (2)^{2} + p (2) - 4 = 0$

$\Rightarrow p = - 2$