If one root of the quadratic equation 2x2+kx−6=0 is 2, then the value of k is
The correct option is A -1Since, 2 is root of the given equation 2x2+kx−6=0.So, it must satisfies the equation. ⇒2(2)2+k(2)−6=08+2k−6=02+2k=0∴k=−1