If one root of the quadratic equation 2x2+kx-6=0 is 2, then the value of k is
1
-1
0
-2
Find the value of k.
Since, the roots of a quadratic polynomial satisfy the polynomial.
⇒222+k2-6=0⇒8+2k-6=0⇒2k=-2⇒k=-1
Hence, option B is correct.
If one root of the quadratic equation 2x2+kx−6=0 is 2, then the value of k is