If one root of the quadratic equation 3x2+5a2x+k=0 is twice the reciprocal of the other root, then the value of k is equal to
A
3
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B
6
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C
5a2
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D
1
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Solution
The correct option is B6 Let α be a root of the quadratic equation 3x2+5a2x+k=0
Then, the other root will be 2α
Now, product of roots =α×2α ⇒α×2α=k3 ⇒k=6
Hence, the correct answer is option (2).