If one root of the quadratic equation ax2−bx−c=0;a,b,c∈R is reciprocal of the other, then which one of the following is correct?
A
a+b=0
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B
b=c
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C
a=c
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D
a+c=0
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Solution
The correct option is Da+c=0 ax2−bx−c=0;a,b,c∈R Since, this is a quadratic equation, so a≠0. Let the roots be α and 1α. So, product of roots is, α×1α=−ca ⇒a=−c ⇒a+c=0