Question

If one root of the quadratic equation $k{x}^2-7x+6=0$ is $2$, then find the value of $k$.

Answer 1

Since, $2$ is root of $k{x}^2-7x+6=0$
$\Rightarrow k(2{)}^2-7\times 2+6=0$
$\Rightarrow 4k-14+6=0$
$\Rightarrow 4k=8$
$\Rightarrow k=2$