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Question

If one root of the quadratic equation kx2 –7x + 12 = 0 is 3, then find the value of k.

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Solution

Given: x = 3 is the root of the quadratic equation kx2 –7x + 12 = 0.

Thus, x = 3 satisfies the given equation.

Therefore,

k(3)2 – 7(3) + 12 = 0

9k – 21 + 12 = 0

9k – 9 = 0

9k = 9

k = 99 = 1

Therefore, the value of k is 1.

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