If one roots of equation x2-3x- - R is -3-2 then other root is

The correct option is A 4 2√(3) let the other root be t Sum of roots = ba=√(3) t+√(3)+2=√(3) t= 2 Product of roots =ca=λ λ= ...

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Standard XII

Mathematics

Roots of a Quadratic Equation

If one roots ...

Question

If one roots of equation $x^{2} - \sqrt{3} x + λ =, λ \in R$ is $\sqrt{3} + 2$ then other root is

- 4 - 2 \sqrt{3}

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- 2

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2 - \sqrt{3}

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2

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Solution

The correct option is A $- 4 - 2 \sqrt{3}$
let the other root be $t$
Sum of roots $= - \frac{b}{a} = \sqrt{3}$
$t + \sqrt{3} + 2 = \sqrt{3}$
$t = - 2$
Product of roots $= \frac{c}{a} = λ$
$λ = (- 2) (2 + \sqrt{3}) = - 4 - 2 \sqrt{3}$

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If one roots of equation x2−√3x+λ=,λ∈R is √3+2 then other root is

The correct option is A −4−2√3let the other root be tSum of roots =−ba=√3t+√3+2=√3t=−2Product of roots =ca=λλ=(−2)(2+√3)=−4−2√3

If one roots of equation $x^{2} - \sqrt{3} x + λ =, λ \in R$ is $\sqrt{3} + 2$ then other root is

The correct option is A $- 4 - 2 \sqrt{3}$
let the other root be $t$
Sum of roots $= - \frac{b}{a} = \sqrt{3}$
$t + \sqrt{3} + 2 = \sqrt{3}$
$t = - 2$
Product of roots $= \frac{c}{a} = λ$
$λ = (- 2) (2 + \sqrt{3}) = - 4 - 2 \sqrt{3}$