Question

If one triose phosphate completely oxidized inside the prokaryotic cell, then the net gain of ATP of energy is equal to

• A. $5$ ATP
• B. $4$ ATP
• C. $20$ ATP
• D. $19$ ATP

Answer 1

The correct option is C $20$ ATP

If one triose phosphate completely oxidized inside the prokaryotic cell, then the net gain of ATP of energy is equal to the summation of the ATPs produced at different steps. In the glycolysis step 2 ATP and 1 NADH will be produced followed by 1 NADH in the gateway reaction and 1 GTP, 3 NADH and 1 FADH2 in the TCA cycle. This will add up to 20 ATPs.

So, the correct option is '20 ATP'.