Question

If one zero of $2x^2-3x+k$ is reciproal to the other, then find the value of $k$.

Answer 1

We have,

$2x^2-3x+k=0$

and one zero is reciprocal to the other.

Let one zero $=x$ then other zero $=\frac{1}{x}$

We know that,

$x\times \frac{1}{x}=\frac{\text{constant}term}{cofficentof{x}^2}$

$1=\frac{k}{2}$

$k=2$

Hence, this is the answer.