Question

If one zero of the polynomial 3x²=8x+2k+1 is seven times the other then find the other zero and the value of k

Answer 1

3x²-8x+2k+1 a=3, b=-8 ,c=2k+1

suppose the zeroes of the equation are α and β . by the given condition α=7β

as we know , α+β=-b/a
7β+β=-(-8)/3
8β=8/3

β=8/3×1/8=1/3
αβ=c/a
7β×β=2k+1/3
7×1/3×1/3=2k+1/3
7/9=2k+1/3

21/9=2k+1
21/9-1=2k
12/9=2k
4/3=2k

4/6=k
2/3=k