If one zero of the polynomial $5 x^{2} + 13 x - k$ is reciprocal of the other, then find k.

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-5

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-3

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Solution

The correct option is B -5
For a polynomial $a x^{2} + b x + c$ ,
product of the zeroes is $\frac{c}{a}$

Here product of the zeroes is one. $(∵$ one root is the reciprocal of other)

$⟹ \frac{- k}{5} = 1$

$k = - 5$

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