Question

If one zero of the polynomial 5z²+13z - p is reciprocal of the other, then find p.

Answer 1

5z 2 +13z-P=0
Compare given eq: ax^2+bx+c=0 Here a=5,b=13,c=-p
Now according to Q's: roots are reciprocal means if one root is x then other will be 1/x ..
We know that peoduct of zeros= c/a => -p/5= x(1/x) => p= -5