If one zero of the polynomial $x^{2} + a$ is -3 then find the its other zero.

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Solution

Given $x^{2} + a$ has one of the zero as $- 3$

$\Rightarrow (- 3)^{2} + a = 0$

$\Rightarrow a + 9 = 0$

$\Rightarrow a = - 9$

So the polynomial is $x^{2} - 9 = (x - 3) (x + 3)$

$\Rightarrow 3, - 3$ are the zeroes

So the other zero is $3$

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