Let a be on of the zero of the polynomial,
According to the question, the other zero of the polynomial is -a,
Sum of Zeroes of the polynomial = a + (-a) = a-a = 0,
We know that, If a quadratic equation such as ax² + bx + c, Then the sum of zeroes of polynomial is -b/a ,
Now from this statement, Sum of Zeroes of given Polynomial is -(-8k)/4,
We can equal them, Since both are sum of zeroes of Polynomial !
=> 8k/4 = 0,
=> 2k = 0,
=> k = 0,
Therefore the value of k is 0,
Read more on Brainl