If one zero of the quadratic polynomial, $f (x) = 4 x^{2} - 8 k x - 9$ is negative of the other, then the value of k is

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Solution

The correct option is A 0
$f (x) = 4 x^{2} - 8 k x - 9 Let the zeroes be α a n d - α Sum of the zeroes = \frac{- b}{a} \Rightarrow α + (- α) = \frac{- (- 8 k)}{4} \Rightarrow 0 = \frac{8 k}{4} \Rightarrow 2 k = 0 ∴ k = 0$
So, option a is correct.

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