Question

If one of the zero of the quadratic polynomial $k{x}^2+3x+k$ is $2$ then find the value of $k$.

Answer 1

Given:

$x=2$ is one of zero of the quadratic polynomial $k{x}^2+3x+k$
Therefore, It will satisfy the above polynomial.
Now, we have
$k\left(2^2\right)+3\left(2\right)+k=0$
$\Rightarrow 4k+6+k=0$
$\Rightarrow 5k+6=0$
$\Rightarrow 5k=-6$
$\therefore k=\frac{-6}{5}$