Question

If only $1\%$ of main current is to be passed through a galvanometer of resistance $G,$ then the value of shunt resistance will be

• A. $\frac{G}{50}$
• B. $\frac{G}{49}$
• C. $\frac{G}{99}$
• D. $99G$

Answer 1

Answer: (C)

$\frac{G}{99}$

If $1\%$ current passes through the galvanometer of resistance $G,99\%$ of current passes through shunt.
$\therefore 0.01I\times G=0.99I\times R_s$
$\Rightarrow R_s=\frac{G}{99}$