If opposite angles in a parallelogram are 110 degrees each, what are the other 2 angles?
70 degrees each
Given that,
Opposite angles in a parallelogram are 110 degrees each.
Let the angles be ∠,∠B,∠C,∠D
Then, ∠A+∠B+∠C+∠D=360∘ [Sum of angles of quadrilateral is 360∘]
2∠+2∠B=360∘ [∵Opposite angles in a parallelogram are 110 degrees each]
⇒220∘+2∠B=360∘ [∵ Opposite angles in a parallelogram are 110 degrees each]
⇒2∠B=360∘−220∘
⇒2∠B=140∘
⇒∠B=70∘