If origin is shifted to $(- 2, 3)$ then transformed equation of curve $x^{2} + 2 y - 3 = 0$ w.r.t $(0, 0)$ is

x^{2} - 4 x + 2 y + 4 = 0

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x^{2} - 4 x - 2 y - 5 = 0

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x^{2} + 4 x + 2 y - 5 = 0

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Solution

The correct option is C $x^{2} + 4 x + 2 y - 5 = 0$
As origin is shifted to point $(- 2, 3)$ ,

So, put, $x = x + 2$ and $y = y - 3$

$⟹ (x + 2)^{2} + 2 (y - 3) - 3 = 0$

$⟹ x^{2} + 4 x + 4 + 2 y - 6 - 3 = 0$

$⟹ x^{2} + 4 x + 2 y - 5 = 0$

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