If osmotic potential of a cell is -10 bars and its pressure potential is 5 bars, its water potential would be

- 5 bars

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 bars

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 10 bars

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 bars

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C - 5 bars
The formula for calculating water potential is $ψ$ = $ψ_{s}$ (osmotic potential) + $ψ_{s}$ (pressure potential). In the given question osmotic potential is -10 bars and pressure potential is 5 bars. So the water potential can be calculated as $ψ$ = -10 bars + 5 bars = -5 bars.
So, the correct answer is '-5 bars'.

Suggest Corrections

Similar questions

The cell A has an osmotic potential of-20 bars and a pressure potential of + 6 bars. What will be its water potential?

Q. Cell A has osmotic potential of –18 bars and pressure potential of 8 bars, whereas cell B has osmotic potential of –14 bars and pressure potential 2 bars. The direction of flow of water will be

Q. Cell-A has osmotic potential of –18 bars and pressure potential of 8 bars, whereas, cell-B has osmotic potential of –14 bars and pressure potential 2 bars. The direction of flow of water will be

Cell A has an osmotic potential of −18 bars and a pressure potential of 8 bars, whereas cell B has an osmotic potential of −14 bars and a pressure potential of 2 bars. The direction of flow of water will be

There are 2 adjacent living cells A & B. The cell ‘A’ has osmotic potential ( $Ψ$ s) of - 7 bars, and pressure potential ( $Ψ_{p}$ ) of 5 bars, whereas cell ‘B’ has osmotic potential ( $Ψ_{s}$ ) of – 8 bars and pressure potential ( $Ψ_{p}$ ) of 3 bars, what will be the direction of water flow in these cells?

Join BYJU'S Learning Program