If osmotic pressure of solution is 0.82 bar at 27°C temperature then what will be the molarity of the solution?

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Solution

T=27degree=300K

We know ,osmotic pressure,π=MRT

Where M is molarity.
Then ,M=π/(RT/

=0.82/(8.314*300)
=0.003287 mol/L

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If osmotic pressure of solution is 0.82 bar at 27°C temperature then what will be the molarity of the solution?

T=27degree=300K We know ,osmotic pressure,π=MRT Where M is molarity. Then ,M=π/(RT/ =0.82/(8.314*300) =0.003287 mol/L

T=27degree=300K

We know ,osmotic pressure,π=MRT

Where M is molarity.
Then ,M=π/(RT/

=0.82/(8.314*300)
=0.003287 mol/L