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Question

If ¯¯¯a+2¯¯b+3¯¯c=0, then ¯¯¯aׯ¯b+¯¯bׯ¯c+¯¯c+¯¯¯a=k(¯¯¯aׯ¯b), when k=

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is D 2
(a×b)(b×a)30+02(b×a3
(a×a)+a×b3+23(a+a)
2(b×a)
k=2

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