If a-2i-2j-k-b-5i-j-2k- then a-b2-a-b2-

The correct option is A 270 Magnitude of Vectors |a⃗|=3 |b⃗|=√(3) (a⃗×b⃗)^2+(a⃗.b⃗)=(a b)^2 =9× 30 =270 ...

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Vector Component

If a=2i+2j+...

Question

If $¯ ¯ ¯ a = 2 ¯ i + 2 ¯ j + ¯ ¯ ¯ k, ¯ ¯ b = 5 ¯ i + ¯ j + 2 ¯ ¯ ¯ k$ , then $(¯ ¯ ¯ a \times ¯ ¯ b)^{2} + (¯ ¯ ¯ a . ¯ ¯ b)^{2} =$

270

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120

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170

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110

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¯ ¯ ¯ a = ¯ i - 2 ¯ j + 3 ¯ ¯ ¯ k, ¯ ¯ b = 2 ¯ i + ¯ j + ¯ ¯ ¯ k, ¯ ¯ c = ¯ i + ¯ j + 2 ¯ ¯ ¯ k

∣ ∣ ∣ (\to a \times \to b) \times ¯ ¯ c ∣ ∣ ∣

∣ ∣ ∣ ¯ ¯ ¯ a \times (\to b \times \to c) ∣ ∣ ∣

[\vec{a} \vec{b} \vec{c}]

\vec{a} = 2 \hat{i} - 3 \hat{j}, \vec{b} = \hat{i} + \hat{j} - \hat{k} and \vec{c} = 3 \hat{i} - \hat{k}

\vec{a} = \hat{i} - 2 \hat{j} + 3 \hat{k}, \vec{b} = 2 \hat{i} + \hat{j} - \hat{k} and \vec{c} = \hat{j} + \hat{k}

\vec{a} = 2 \hat{i} + 3 \hat{j} + \hat{k}, \vec{b} = \hat{i} - 2 \hat{j} + \hat{k} and \vec{c} = - 3 \hat{i} + \hat{j} + 2 \hat{k}

\vec{a} \cdot \vec{b}

\vec{a} = \hat{i} - 2 \hat{j} + \hat{k} and \vec{b} = 4 \hat{i} - 4 \hat{j} + 7 \hat{k}

\vec{a} = \hat{j} + 2 \hat{k} and \vec{b} = 2 \hat{i} + \hat{k}

\vec{a} = \hat{j} - \hat{k} and \vec{b} = 2 \hat{i} + 3 \hat{j} - 2 \hat{k}

\vec{a} and \vec{b}

\vec{a} = λ \hat{i} + 2 \hat{j} + \hat{k} and \vec{b} = 4 \hat{i} - 9 \hat{j} + 2 \hat{k}

\vec{a} = λ \hat{i} + 2 \hat{j} + \hat{k} and \vec{b} = 5 \hat{i} - 9 \hat{j} + 2 \hat{k}

\vec{a} = 2 \hat{i} + 3 \hat{j} + 4 \hat{k} and \vec{b} = 3 \hat{i} + 2 \hat{j} - λ \hat{k}

\vec{a} = λ \hat{i} + 3 \hat{j} + 2 \hat{k} and \vec{b} = \hat{i} - \hat{j} + 3 \hat{k}

\vec{a} = 2 \hat{i} + 3 \hat{j} + 4 \hat{k}, \vec{b} = \hat{i} + 2 \hat{j} - \hat{k}, \vec{c} = 3 \hat{i} - \hat{j} + 2 \hat{k}

\vec{a} = 2 \hat{i} - 3 \hat{j} + 4 \hat{k}, \vec{b} = \hat{i} + 2 \hat{j} - \hat{k}, \vec{c} = 3 \hat{i} - \hat{j} - 2 \hat{k}

\vec{a} = 11 \hat{i}, \vec{b} = 2 \hat{j}, \vec{c} = 13 \hat{k}

\vec{a} = \hat{i} + \hat{j} + \hat{k}, \vec{b} = \hat{i} - \hat{j} + \hat{k}, \vec{c} = \hat{i} + 2 \hat{j} - \hat{k}

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