If ¯¯¯a and ¯¯b are unit vectors, then the vector (¯¯¯a+¯¯b)×(¯¯¯aׯ¯b) is parallel to the vector
A
¯¯¯a−¯¯b
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B
¯¯¯a+¯¯b
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C
2¯¯¯a−¯¯b
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D
2¯¯¯a+¯¯b
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Solution
The correct option is B¯¯¯a−¯¯b (¯¯¯a+¯¯b)×(¯¯¯aׯ¯b) =¯¯¯a((¯¯¯a+¯¯b).¯¯b)−¯¯b((¯¯¯a+¯¯b).¯¯¯a) =¯¯¯a(¯¯¯a.¯¯b+¯¯b.¯¯b)−¯¯b(¯¯¯a.¯¯¯a+¯¯b.¯¯¯a) =¯¯¯a(ab+1)−¯¯b(1+ab) =(¯¯¯a¯¯b+1)(¯¯¯a−¯¯b)