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Question

If ¯¯¯a=^i+^j2^k,¯¯b=2^i0^j+^k,¯¯c=3^i^k and ¯¯c=m¯¯¯a+n¯¯b then m+n=.........

A
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B
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C
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D
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Solution

The correct option is C 2
c=ma+nb=m(i+j2k)+n(2i0j+k)=(m+2n)i+mj+(n2m)kButc=3ikm+2n=3,n2m=1Solvingitwewillgetm=1,n=1m+n=1+1=2

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