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Question

If (¯¯¯a,¯¯b)=π, then |4¯¯¯a×5¯¯b+¯¯bׯ¯¯a|=

A
0
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B
19|¯¯¯a||¯¯b|
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C
|¯¯¯a||¯¯b|
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D
2|¯¯¯a||¯¯b|
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Solution

The correct option is A 0
|4¯¯¯a×5¯¯b+¯¯bׯ¯¯a|
=|20¯¯¯aׯ¯b¯¯¯aׯ¯b|
=|19¯¯¯aׯ¯b|
=19|¯¯¯a||¯¯b|sinπ
=0.

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