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Question

If ¯¯¯a=¯i2¯j+3¯¯¯k,¯¯b=2¯i+¯j+¯¯¯k,¯¯c=¯i+¯j+2¯¯¯k then find (a×b)ׯ¯c and ¯¯¯a×(b×c).

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Solution

a×(b×c)=(ac)b(ab)c=5b3c=7^i+2^j^k
(a×b)×c=(ac)b(bc)a=5b5a=5(^i+3^j2^k)
|(a×b)×c|=51+9+4=514
and |a×(b×c)|=49+4+1=54=36.

1131038_1208921_ans_6cb60de937ed44ed85146e034a8a4c82.jpg

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