If ¯¯¯a=¯i+¯j+¯¯¯k,¯¯b=2¯i−3¯j+¯¯¯k, then ¯¯¯aׯ¯b|¯¯¯aׯ¯b|+¯¯bׯ¯¯a|¯¯bׯ¯¯a|=
A
¯¯¯0
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B
2¯i+¯j−2¯¯¯k
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C
¯i+¯j+2¯¯¯k
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D
¯i+2¯j−¯¯¯k
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Solution
The correct option is B¯¯¯0 ¯¯¯aׯ¯b=−(¯¯bׯ¯¯a) Also, |¯¯¯aׯ¯b|=|(¯¯bׯ¯¯a)| Thus, the denominators become equal and the numerator adds up to 0. Hence the answer becomes 0.